Question

A ball is released from the top of tower of height $h$ meter. It takes $T$ second to reach the ground. What is the position in $\text{(m)}$ from the ground of the ball in $\frac{T}{3}$ second?

• A. $\frac{h}{9}$
• B. $\frac{8h}{9}$
• C. $\frac{5h}{9}$
• D. $\frac{7h}{9}$

Answer 1

The correct option is B $\frac{8h}{9}$

As per the question, height of the tower is given by
$h=\frac{1}{2}g{T}^2$
Similarly, the distance travelled in $\frac{T}{3}\text{sec}$ is given by
$s=\frac{1}{2}g{\left(\frac{T}{3}\right)}^2=\frac{h}{9}$
Thus, position of the ball from the ground is $h-\frac{h}{9}=\frac{8h}{9}\text{m}$