A ball is shot vertically upward with a given initial velocity. It reaches a maximum height of 100m. If on a second shot, the initial velocity is doubled then the ball will reach a maximum height of.
A
70.7m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
141.4m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
200m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
400m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D400m Let initial velocity of ball=u By IIIrd equation H=u22g=100m If initial velocity is doubled H′=(2u)22g=4⋅u22g=4×100 H′=400m.