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Question

A ball is shot vertically upward with a given initial velocity. It reaches a maximum height of 100 m. If in the second shot the initial velocity is doubled then the ball will reach a maximum height of

A
70.7 m
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B
141.4 m
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C
200 m
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D
400 m
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Solution

The correct option is D 400 m
Let the initial velocity at the first shot be u, then from third equation of motion
v2=u2+2aS
O=u22g(100)
u2=2g(100)
Now, for the second shot similarly
(2u)2=2g(H)
4u2=2gH
4(2g(100))=2gH
H=400 m
Therefore, option D is correct.

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