A ball is shot vertically upward with a given initial velocity. It reaches a maximum height of 100m. If in the second shot the initial velocity is doubled then the ball will reach a maximum height of
A
70.7m
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B
141.4m
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C
200m
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D
400m
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Solution
The correct option is D400m Let the initial velocity at the first shot be u, then from third equation of motion v2=u2+2aS O=u2–2g(100) u2=2g(100)
Now, for the second shot similarly (2u)2=2g(H) 4u2=2gH 4(2g(100))=2gH H=400m
Therefore, option D is correct.