A ball is thrown at a speed of $40 m / s$ at an angle of $60^{o}$ with the horizontal. Find (a) the maximum height reached and (b) the range of the ball . Take $g = 10 m / S^{2}$

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Solution

Given $u = 40 m / s$ , $θ = 60^{0}$ and $g = 10 m / s^{2}$

Maximum Height $H_{M a x} = \frac{u^{2} s i n^{2} θ}{2 g} = 60 m$

Range $R = \frac{u^{2} s i n 2 θ}{g} = 80 \sqrt[2]{3} m$

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A ball is thrown at a speed of 40m/s at an angle of 60o with the horizontal. Find (a) the maximum height reached and (b) the range of the ball . Take g=10m/S2

Given u=40m/s, θ=600 and g=10m/s2Maximum Height HMax=u2sin2θ2g=60mRange R=u2sin2θg=802√3m

A ball is thrown at a speed of $40 m / s$ at an angle of $60^{o}$ with the horizontal. Find (a) the maximum height reached and (b) the range of the ball . Take $g = 10 m / S^{2}$

Given $u = 40 m / s$ , $θ = 60^{0}$ and $g = 10 m / s^{2}$

Maximum Height $H_{M a x} = \frac{u^{2} s i n^{2} θ}{2 g} = 60 m$

Range $R = \frac{u^{2} s i n 2 θ}{g} = 80 \sqrt[2]{3} m$