A ball is thrown at angle above horizontal of some height with the some velocity. Time taken for ball to reach first wall and second wall is equal to $T_{1} a n d T_{2}$ respectively. Find $T_{1} + T_{2} (T = t i m e o f f l i g h t)$

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Solution

The correct option is A T
$T_{t}$ = time to reach the first wall + time to move from first wall to second wall + time to move from second
= $T_{1} + (T_{2} - T_{1}) + T_{1}$
= $T_{1} + T_{2}$
= T

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