Question

A ball is thrown directly upwards and reaches a maximum height $h$. When it is at height $h/2$, its speed relative to the initial speed $v_0$ it had when it was originally thrown is:

• A. $\sqrt{v_0^2-gh}$
• B. $\sqrt{v_0^2-2gh}$
• C. $\sqrt{2v_0^2-gh}$
• D. $\sqrt{2v_0^2-2gh}$
• E. None of the above

Answer 1

The correct option is A $\sqrt{v_0^2-gh}$

Given - $height=h/2,u=v_0$

by using $v^2=u^2-2gh$

$v^2=v_0^2-2gh/2$

or $v=\sqrt{v_0^2-gh}$