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Question

A ball is thrown from the ground level so as to just clear a wall at a distance of a meters and it falls at a distance of b meters from the foot of the wall. If the angle of projection is 45∘, find the height of the wall.

A
h=aa+b
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B
h=ba+b
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C
h=aba+b
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D
h=ab
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Solution

The correct option is C h=aba+bLet the given condition be as shown in the below figure Given, θ=45∘ Let h be the height of the wall From the figure, R=a+b By equation of trajectory of a projectile, we know y=xtanθ(1−xR)⇒ h=a(1)(1−aa+b) ⇒ h=aba+b

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