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Question

# A ball is thrown from the ground to clear a wall 3m high at a distance of 6m and falls 18m away from the wall, the angle of projection of ball is :

A
tan1(32)
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B
tan1(23)
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C
tan1(12)
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D
tan1(34)
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Solution

## The correct option is B tan−1(23)We know that range of a projectileR=U2sin2θgHere R=6+18=24∴U2sin2θg=24 .....(i)The equation of trajectory of a projectiley=xtanθ−gx22U2cos2θ3=6tanθ−36g2U2cos2θ ....(ii)From equation (i), gU2=sin2θ24 =sinθcosθ12Substituting in equation (ii), we get3=6tanθ−32tanθ3=92tanθ⇒θ=tan−1(23)

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