CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

A ball is thrown on downwards with initial speed=6 m/s, from a point at height=3.2 m above a horizontal floor. If the ball rebounds back to the same height then coefficient of restitution equal to:

A
1/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.75
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.8
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 0.8
Final velocity v of the ball=u2+2gs=36+2×10×3.2=10m/s
Now for the ball return flight after rebounding, since it just reaches height 3.2m final velocity=0
To reach height 3.2m initial velocity require u=2×10×3.2=8m/s
Coefficiet of restitution:
CR=K.EafterimpactK.Ebeforeimpact= 12mv212mu2=v2u2=vu
CR=810=0.8

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon