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Question

A ball is thrown on downwards with initial speed=6 m/s, from a point at height=3.2 m above a horizontal floor. If the ball rebounds back to the same height then coefficient of restitution equal to:

A
1/2
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B
0.75
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C
0.8
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D
None
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Solution

The correct option is C 0.8
Final velocity v of the ball=u2+2gs=36+2×10×3.2=10m/s
Now for the ball return flight after rebounding, since it just reaches height 3.2m final velocity=0
To reach height 3.2m initial velocity require u=2×10×3.2=8m/s
Coefficiet of restitution:
CR=K.EafterimpactK.Ebeforeimpact= 12mv212mu2=v2u2=vu
CR=810=0.8

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