A ball is thrown up vertically with speed u. At the same instant another ball b is released from rest at height h vertically above the point of projection A taking the moment of projection of A .Taking the moment of projection as t=0 and acceleration due to gravity is g at the momment of collision the position of a is at a distance?

Open in App

Solution

Suggest Corrections

Similar questions

Q. Ball I is thrown towards a tower at an angle of

60^{o}

with the horizontal with unknown speed (u). At the same moment, ball II is released from the top of tower as shown in Fig. Balls collide after 2 s and at the moment of collision, the velocity of ball I is horizontal. Find the
a. speed

u

b. distance of point of projection of ball I from base of tower (x)
c. height of tower

Q. Ball A is thrown up vertically with speed

10

m/s At the same instant another ball B is released from rest at height

Q. Ball

A

is thrown up vertically with speed

10 m / s

. At the same instant another ball

B

is released from rest at height

h

. At time

t

, the speed of

A

relative to

B

Q. A ball is thrown vertically upward from the top of a cliff. Take the starting position of motion as origin and upward direction as positive. Column I specifies the position, velocity and /or acceleration of the particle at any instant. Column II given their signs

(+)

(-)

at that moment. Match the columns

\begin{matrix} Column I & Column II i.When the ball is above the point & a. always positive of projection, its displacement is ii. When the ball is above the point & b. always negative of projection, its velocity is iii. When the ball is above the point & c. May be positive or may be of projection, its acceleration is & negative iv.When the ball is below the point & d. may be zero of projection, its acceleration is \end{matrix}

A ball A is thrown up vertically with speed u.At the same instant another ball B is released from rest at height h.At time t speed of A relative to B is ?

Join BYJU'S Learning Program