A ball is thrown up with a velocity of $10 m / s$ . The maximum height it reaches is:
(Take $g = 10 m / s^{2}$ )

15 m

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5 m

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2.5 m

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10 m

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Solution

The correct option is B $5 m$
Let the upward direction be positive.
Given:
Ball is thrown upwards. So, $u = + 10 m / s$
At maximum height, the ball reverses its direction. So, its speed is zero. Or, the final velocity is zero.
$v = 0$
Acceleration due to gravity is in the downward direction. So,
$a = - g = - 10 m / s^{2}$

Let the displacement be $s$ .

Using third equation of motion,
$v^{2} = u^{2} + 2 a s$
Substituting values,
$0^{2} = 10^{2} + 2 \times - 10 \times s$
$s = 5 m$

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A ball is thrown up with a velocity of 10 m/s. The maximum height it reaches is: (Take g=10 m/s2)

A ball is thrown up with a velocity of $10 m / s$ . The maximum height it reaches is:
(Take $g = 10 m / s^{2}$ )