Question

A ball is thrown upward from edge of a cliff with an initial velocity of 6 m/s . How fast is it moving 1/2 s later ?(g=10 $m/s^2$)

Answer 1

Given,

Initial velocity of ball , $u=6m/s$

acceleration on the ball, $a=-g=-10m/s^2$

Using

$v=u+at$

Here $t=\frac{1}{2}sec$

Final velocity, $v=6-10\times \frac{1}{2}=1m/s$