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Question

A ball is thrown upward with an initial velocity of 100ms−1. Draw velocity-time graph for the ball and find from the graph height of the ball after 15s. Take g=10ms−2.

A
125m
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B
375m
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C
500m
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D
625m
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Solution

The correct option is A 375m
Initial velocity of the ball u=100 m/s
Acceleration of the ball a=g=10 m/s2
Using v=u+at
v=10010t
Thus vt graph is a straight line intersecting the t axis at t=10 s
Also vt=15=10010(15)=50 m/s2
Height (displacement) of the ball is equal to the area under the curve during 0<t<15
h=12×100×1012×(1510)×50=375 m

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