A ball is thrown upwards. Its height varies with time as follows:
If the acceleration due to gravity is $7.5 m / s^{2}$ , then the height $h$ is :

10 m

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15 m

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20 m

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25 m

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Solution

The correct option is B $15 m$

Velocity at highest point becomes zero

$∴ 0 = u - a t$

or $u = a t$

$= 7.5 \times 3.5 = 62.25 m / s$
$y_{1} = u \times 1 - \frac{1}{2} \times 7.5 \times 1^{2}$

$y_{2} = u \times 2 - \frac{1}{2} \times 7.5 \times 2^{2}$

$h = y_{2} - y_{1} = 15$

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A ball is thrown upwards. Its height varies with time as follows:If the acceleration due to gravity is 7.5m/s2, then the height h is :

The correct option is B 15m Velocity at highest point becomes zero ∴0=u−at or u=at =7.5×3.5=62.25m/s y1=u×1−12×7.5×12 y2=u×2−12×7.5×22 h=y2−y1=15

A ball is thrown upwards. Its height varies with time as follows:
If the acceleration due to gravity is $7.5 m / s^{2}$ , then the height $h$ is :

The correct option is B $15 m$

Velocity at highest point becomes zero

$∴ 0 = u - a t$

or $u = a t$

$= 7.5 \times 3.5 = 62.25 m / s$
$y_{1} = u \times 1 - \frac{1}{2} \times 7.5 \times 1^{2}$

$y_{2} = u \times 2 - \frac{1}{2} \times 7.5 \times 2^{2}$

$h = y_{2} - y_{1} = 15$