Question

A ball is thrown upwards with a velocity of $10\frac{m}{s}$. Find the maximum height reached by the ball.

• A. 13 m
• B. 5 m
• C. 15 m
• D. 16 m

Answer 1

The correct option is B

5 m

Since acceleration due to gravity is opposite to the motion. At some point of motion, velocity will become zero. At that moment, the ball will change the direction of motion and fall downwards. Thus at maximum height, velocity will be zero.

Initial velocity $u=10\frac{m}{s}$

final velocity $v=0\frac{m}{s}$

$v^2$​ = $u^2+2as$

Since, acceleration due to gravity is opposite to direction of velocity,
Acceleration due to gravity $=-10\frac{m}{s^2}$
0 = 100 + 2 $\times$ (-10) $\times$ s
s = 5 m