A ball is thrown upwards with a velocity of $25 m / s$ . What is the time taken by the ball to return to the thrower ( $g = 10 m / s^{2}$ )

5 s e c

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2.5 s e c

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3 s e c

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4.2 s e c

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Solution

The correct option is A $5 s e c$
Initial velocity of the ball final velocity $= 0 m / s$
acceleration due to gravity $(g) = - 10 m / s$ $^{2}$ (upward motion)
By using the formula,
$v = u + a t$
$O = 25 + (- 10) \times t$
$10 t = 25$
$t = 2.5 s e c .$
The time taken for upward journey is equal to the time taken for downward journey.
Therefore, total time taken by the ball $= 2.5 + 2.5 = 5 s e c .$

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A ball is thrown upwards with a velocity of 25m/s. What is the time taken by the ball to return to the thrower (g=10m/s2)

A ball is thrown upwards with a velocity of $25 m / s$ . What is the time taken by the ball to return to the thrower ( $g = 10 m / s^{2}$ )