A ball is thrown vertically attains a maximum height of 45 m. The time after which velocity of the ball becomes equal to half the velocity of projection? (use g = $10 m / s^{2}$ ) is ___.

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1.5s

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0.5s

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Solution

The correct option is B 1.5s
Case I : Let initial velocity be u.
$2 a s = u^{2} - u^{2}$
$- 2.10.45 = 0 - u^{2}$
$+ 900 = u^{2}$
u = 30 m/sec.
At 45 m, velocity of the ball will be zero.
Case II : v = u at
U = half of projection velocity
$= \frac{30}{2} = 15 m / s e c$
$15 = 0 + 10 \times t$
$1.5 = t$ .

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A ball is thrown vertically attains a maximum height of 45 m. The time after which velocity of the ball becomes equal to half the velocity of projection? (use g = 10 m/s2) is ___.

The correct option is B 1.5sCase I : Let initial velocity be u. 2as=u2−u2 −2.10.45=0−u2 +900=u2 u = 30 m/sec. At 45 m, velocity of the ball will be zero. Case II : v = u at U = half of projection velocity =302=15m/sec 15=0+10×t 1.5=t.

A ball is thrown vertically attains a maximum height of 45 m. The time after which velocity of the ball becomes equal to half the velocity of projection? (use g = $10 m / s^{2}$ ) is ___.