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Question

A ball is thrown vertically up from a tower of height 60 m with a speed of 20 m/s. The vt curve of the ball is
[Take upward positive and g=10 m/s2]

A
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B
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C
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Solution

The correct option is B
Given, height of the building h=60 m, initial speed of the ball u=20 m/s
The velocity of the ball is given as
v=u+at v=2010t
So, at t=2 sec, the ball will be at maximum height and velocity will be zero.
Now, we will find the time of flight of the ball using the equation s=ut+12at2 and T=2ug
So, time taken to cover building height is given by
60=20t12×10×t2
On solving the equation we get t=2 sec
Also, time taken by ball to come at the same level from where it was thrown is given by
T=2ug=2×2010=4 sec
So, the ball will take 2+4=6 sec to reach the ground
Hence, the striking velocity of the ball will be
v=2010×6=40 m/s
Thus, the situation can be shown as

The vt graph would be

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