A ball is thrown vertically up from ground with a velocity of 50ms−1. Find the total distance travelled by the ball just before reaching ground.
A
250m
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B
122.5m
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C
117.5m
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D
140m
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Solution
The correct option is A250m Let the final velocity of the ball on reaching the maximum height be ‘v′. This v=0 as the ball will momentarily stop at the highest point. By third equation of motion. v2−u2=2as 02−502=2(−10)s −2500=20s Or, s=125m This is half of the total distance travelled by the ball. Total distance travelled =2×s=250m