Question

A ball is thrown vertically upward with a velocity of $60m/s$. The maximum height to which the ball rises is

Answer 1

Step 1: Given Data

Initial velocity $u=60m/s$

Final velocity $v=0$

Let the acceleration due to gravity be $g=9.8m/s^2$

Let the maximum height to which the ball rises be $h$.

Step 2: Formula Used

Since the ball is moving upwards, the value of $g$ will be taken as negative.

According to Newton's third law of motion

$v^2=u^2-2gh$

Step 3: Calculate the Height

Upon substituting the values we get,

$0={60}^2-2\times 9.8\times h$

$\Rightarrow h=\frac{{60}^2}{2\times 9.8}$

$\Rightarrow h=183.7m$

Hence, the maximum height to which the ball rises is $183.7m$.