A ball is thrown vertically upwards and reaches the maximum height in 3 seconds. Find the initial velocity and height reached by the ball
v = 0 (at max height)
t = 3 sec
a = 10 m/s²
Find u and s.
1st equation of motion:
v = u + at
0 = u - 10 (3) (- sign because a is in opposite direction of u)
Initial velocity , u = 30 m/s
v²-u² = 2as
0 - (30)² = 2 (-10) s
900/20 = s
maximum height reached , S = 45 m