A ball is thrown vertically upwards from the top of a tower at 4.9 m/s . it strikes the ground near the base of the tower after 3 seconds . The height of the tower is

73.5

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44.1

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29.4

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14.7

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Solution

The correct option is C $29.4$
$S = u t + (g t) . S = h e i g h t o f t o w e r = i n i t i a l s p e e d = - 4.9 m / s . (U p w a r d h e n c e - v e .) T = t i m e = 3 s e c$
$g = 9.8 m / s . O n s o l v i n g s = 29.4 m$

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A ball is thrown vertically upwards from the top of a tower at 4.9 m/s . it strikes the ground near the base of the tower after 3 seconds . The height of the tower is

The correct option is C 29.4S=ut+(gt).S=height of tower=initialspeed=−4.9m/s.(Upwardhence−ve.)T=time=3secg=9.8m/s.Onsolvings=29.4m

The correct option is C $29.4$
$S = u t + (g t) . S = h e i g h t o f t o w e r = i n i t i a l s p e e d = - 4.9 m / s . (U p w a r d h e n c e - v e .) T = t i m e = 3 s e c$
$g = 9.8 m / s . O n s o l v i n g s = 29.4 m$