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Standard XII

Physics

Applications of Horizontal and Vertical Components

A ball is thr...

Question

A ball is thrown vertically upwards from the top of a tower with a velocity of 10 m/sec. If the ball falls on the ground after 5 seconds, the height of the tower will be $(use g = 10 m / s^{2})$

25 m

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50 m

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75 m

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100 m

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Solution

The correct option is D 100 m
We know that,
$s = + u t + \frac{1}{2} a t^{2} s = + (10) (5) + \frac{1}{2} (10) (5)^{2} s = + 50 + \frac{1}{2} \times 10 \times 25 s = 50 + 50 m = 100 m$

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A ball is thrown vertically upwards from the top of a tower with a velocity of 10 m/sec. If the ball falls on the ground after 5 seconds, the height of the tower will be (useg=10m/s2)

The correct option is D 100 mWe know that,s=+ut+12at2s=+(10)(5)+12(10)(5)2s=+50+12×10×25s=50+50m=100m

A ball is thrown vertically upwards from the top of a tower with a velocity of 10 m/sec. If the ball falls on the ground after 5 seconds, the height of the tower will be $(use g = 10 m / s^{2})$

The correct option is D 100 m
We know that,
$s = + u t + \frac{1}{2} a t^{2} s = + (10) (5) + \frac{1}{2} (10) (5)^{2} s = + 50 + \frac{1}{2} \times 10 \times 25 s = 50 + 50 m = 100 m$