A ball is thrown vertically upwards with a given velocity such that it rises for T seconds (T > 1). What is the distance traversed by the ball during the last one second of ascent (in meters) ? (Acceleration due to gravity is g $m / s^{2}$ ) .

v + g \frac{(1 - 2 T)}{2}

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v T + \frac{1}{2} g [T^{2} - (T - 1)^{2}]

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\frac{g}{2}

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\frac{1}{2} g [T^{2} - (T - 1)^{2}]

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Solution

The correct option is C $\frac{g}{2}$

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A ball is thrown vertically upwards with a given velocity such that it rises for T seconds (T > 1). What is the distance traversed by the ball during the last one second of ascent (in meters) ? (Acceleration due to gravity is g m/s2 ) .

The correct option is C g2

A ball is thrown vertically upwards with a given velocity such that it rises for T seconds (T > 1). What is the distance traversed by the ball during the last one second of ascent (in meters) ? (Acceleration due to gravity is g $m / s^{2}$ ) .

The correct option is C $\frac{g}{2}$