A ball is thrown vertically upwards with a velocity of $10 m / s$ from a height of $4 m$ from the ground. If the air resistance is neglected and $g = 9.8 m / s^{2}$ , the time taken by the ball to reach the ground is

2.01 s

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2.53 s

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2.86 s

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4.09 s

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Solution

The correct option is D 4.09 s
$S = u t - \frac{1}{2} g t^{2}$

$S = - 40 m and u = 10 m / s$

$- 40 = 10 t - \frac{9.8}{2} t^{2} \Rightarrow t = 4.09 s e c$

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