A ball is thrown vertically upwards with a velocity of $10 m s^{-} 1$ . IT returns to the ground with a velocity of $9 m s^{-} 1$ . If $g = 9.8 m s^{-} 2$ , then the maximum height attained by the ball is nearly ( assume a resistance to be uniform)

5.1 m

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4.1 m

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4.61 m

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5 m

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Solution

The correct option is A 5.1 m
Given,
$u = 10 m / s$
$g = - 9.8 m / s^{2}$
$v = 0 m / s$
Lets consider, $H =$ maximum height attained by the ball
From 2nd equation of motion,
$2 a s = v^{2} - u^{2}$
$H = \frac{v^{2} - u^{2}}{2 g}$
$H = \frac{0^{2} - 10 \times 10}{- 2 \times 9.8}$
$H = 5.1 m$
The correct option is A.

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A ball is thrown vertically upwards with a velocity of 10ms−1. IT returns to the ground with a velocity of9ms−1. If g=9.8ms−2, then the maximum height attained by the ball is nearly ( assume a resistance to be uniform)

The correct option is A 5.1 mGiven,u=10m/sg=−9.8m/s2v=0m/sLets consider, H= maximum height attained by the ballFrom 2nd equation of motion,2as=v2−u2H=v2−u22gH=02−10×10−2×9.8H=5.1mThe correct option is A.

A ball is thrown vertically upwards with a velocity of $10 m s^{-} 1$ . IT returns to the ground with a velocity of $9 m s^{-} 1$ . If $g = 9.8 m s^{-} 2$ , then the maximum height attained by the ball is nearly ( assume a resistance to be uniform)