A ball is thrown vertically upwards with a velocity of 10m/s. It returns to the ground with velocity of 9m/s. If g=9.8m/s2, then the maximum height attained by the ball is nearly (assume air resistance to be uniform)
A
5.1m
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B
4.1m
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C
4.61m
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D
5.0m
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Solution
The correct option is C4.61m Total energy loss due to air friction =Ki−Kf=12m(100−81) =192m(m=mass)
Half of the loss will be in upward journey.
Hence, mgh+12(192m)=Ki=12m(100)=50m ∴h=4.61m