Question

# A ball is thrown vertically upwards with a velocity of 20 m $$s^{-1}$$ from the top of a multistorey building of 25 m high. How high will the ball rise from top of the building? (Take g = 10 m $$s^{-2}$$).

A
10 m
B
15 m
C
20 m
D
25 m

Solution

## The correct option is C 20 mTaking upward direction as $$+ve,$$$$u=+20m/s\\a=-g=-10m/s^2$$At maximum height, $$v=0.$$By third law of motion,$$v^2=u^2+2as\\o^2=(20)^2+2(-10)(s)\\ \Longrightarrow -400=20s\\s=20m$$Physics

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