Question

A ball is thrown vertically upwards with a velocity of $49m{s}^{-1}$. Calculate the maximum height to which it rises.

• A. 122.5 m
• B. 100 m
• C. 22.5 m
• D. 78 m

Answer 1

The correct option is A 122.5 m

$v^2=u^2+2as$
$v=0m/s$
$u=49m/s$
$a=-9.8m/s^2$ (for upward direction gravity is -ve)
$0^2={49}^2+2(-9.8)s$
$s=\frac{49\times 49}{2\times 9.8}=122.5m$