A ball is thrown with initial velocity of 10 m/s at an angle of 23o with horizontal surface. How far away does the ball land? Given that sin 23o = 0.4, cos 23o = 0.9, and g = 10m/s2and ignore the effect of air resistance.
A
3.6 m
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B
4.0 m
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C
4.5 m
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D
7.2 m
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E
9.0 m
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Solution
The correct option is A 7.2 m Given : u=10 m/s θ=23og=10m/s2
Horizontal range of particle R=u2sin2θg=2u2sinθcosθg=2×102×0.4×0.910=7.2 m