A ball moving with a moment of $15 k g {m s}^{- 1}$ strikes against a wall at $60^{o}$ angle and is reflected at the same angle with its initial speed. Find the impulse.

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Solution

Impulse = Change in Momentum $(Δ p) = \sqrt{p_{1}^{2} + p_{2}^{2} + 2 p_{1} p_{2} cos θ} = 2 p cos (\frac{θ}{2})$

$= 2 \times 15 cos (\frac{60}{2})$

$= 30 \times \frac{\sqrt{3}}{2}$

$= 15 \sqrt{3} k g m / s$

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A ball moving with a moment of 15 kgms−1 strikes against a wall at 60o angle and is reflected at the same angle with its initial speed. Find the impulse.

Impulse = Change in Momentum (Δp)=√p21+p22+2p1p2cosθ=2pcos(θ2)=2×15cos(602)=30×√32=15√3kgm/s

A ball moving with a moment of $15 k g {m s}^{- 1}$ strikes against a wall at $60^{o}$ angle and is reflected at the same angle with its initial speed. Find the impulse.

Impulse = Change in Momentum $(Δ p) = \sqrt{p_{1}^{2} + p_{2}^{2} + 2 p_{1} p_{2} cos θ} = 2 p cos (\frac{θ}{2})$

$= 2 \times 15 cos (\frac{60}{2})$

$= 30 \times \frac{\sqrt{3}}{2}$

$= 15 \sqrt{3} k g m / s$