A ball moving with velocity 10m/s in downward direction as shown in figure. After collision with fixed surface having coefficient of restitution e=0.5, it rebounds back with velocity v m/s. Find the value of v. (Neglect all external forces)
A
5 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
10 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
15 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A5 m/s
As surface is fixed. ∴velocity of the surface before collision (→u2)=0 m/s Velocity of surface after collision (→v2)=0 m/s
We know Coefficient of restitution, (e)=v2−v1u1−u2=0−(v)(−10)−0 (Taking upward velocity + ve) ⇒0.5=v10⇒v=5 m/s