wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A ball moving with velocity 2 ms−1 collides head-on with another stationary ball of double the mass. If the coefficient of restitution is 0.5, then their velocities (in ms−1) after collision will be

A
0,1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1,1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1,0.5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0,2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0,1
When two bodies collide head-on,
Coefficient of restitution, e=v2v1u1u2
From law of conservation of momentum
m1u1+m2u2=m1v1+m2v2
Put, u1=2 ms1,u2=0,m1=m
and m2=2m,e=0.5
Combining the above two equations:
v1=[mmm+2m]×2
v1=0
v2=[1.5×m3m]×2
v2=1 ms1

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon