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Byju's Answer

Standard XII

Physics

Angular Analogue of Linear Momentum

A ball moving...

Question

A ball moving with velocity of $9 m / s$ collides with another similar stationary ball. After the collision both the balls move in directions making an angle of $30^{o}$ with the initial direction. After the collision their speed will be?

2.6 m / s

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5.2 m / s

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0.52 m / s

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52 m / s

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Solution

The correct option is A $2.6 m / s$
$2.6 m / s$

$m v 1 sin 60^{\circ} - m v 2 sin 60^{\circ} = 0$

$v 1 = v 2$

conservation of linear momentum in the direction of initial velocity of the first ball:

$m u = m v 1 cos 30^{\circ} + m v 2 cos 30^{\circ}$

$9 = 2 v cos 30 = 2 \sqrt{3} v$

$v = \frac{3 \sqrt{3}}{2} m / s = 2.6 m / s$

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A ball moving with velocity of 9 m/s collides with another similar stationary ball. After the collision both the balls move in directions making an angle of 30o with the initial direction. After the collision their speed will be?

The correct option is A 2.6 m/s2.6m/smv1sin60∘−mv2sin60∘=0 v1=v2conservation of linear momentum in the direction of initial velocity of the first ball: mu=mv1cos30∘+mv2cos30∘9=2vcos30=2√3vv=3√32m/s=2.6m/s

A ball moving with velocity of $9 m / s$ collides with another similar stationary ball. After the collision both the balls move in directions making an angle of $30^{o}$ with the initial direction. After the collision their speed will be?