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Question

A ball of 1 gm rolls down an inclined plane and describes a circle of radius 10 cm in the vertical plane on reaching the bottom. The minimum height of the inclined plane is :

A
35 cm
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B
52cm
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C
25 cm
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D
53cm
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Solution

The correct option is A 35 cm
R=10cm. (given)
In case of Solid spherical ball.
For no slipping
V bottom =5gR
(for completing vertical circular motion)
for finding this velocity we can apply apply Work Energy Theorem
mgH=12mV2+12×25×mR2(VR)2
10H=710V2
H=7100×5×10×10100
H=0.35m
=35cm

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