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Question

A ball of 2 kg strikes a wall with a velocity 1 m/s at an angle 30 with the horizontal as shown in the figure below. It reflects at the same angle from the wall in 0.1 s. Force exerted on the ball will be:


A
203 N
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B
153 N
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C
103 N
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D
53 N
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Solution

The correct option is A 203 N


Change in momentum of ball perpendicular to the wall =m(vcosθ(vcosθ))
(taking rightwards +ve)
=2mvcosθ=2×2×1×cos30=2×2×32=23 kg m/s
We know that force is equal to rate of change of momentum
So, Rate of change of momentum
=change in momentumtime=230.1=203 NForce on the ball=203 N

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