Question

A ball of mass $0.15\text{kg}$ hits the wall with its initial speed of $12{\text{ms}}^{-1}$ and bounces back without changing its initial speed. If the force applied by the wall on the ball during the contact is $100\text{N}$, calculate the time duration of the contact of ball with the wall.

• A. $0.036\text{s}$
• B. $0.018\text{s}$
• C. $0.072\text{s}$
• D. $0.009\text{s}$

Answer 1

The correct option is A $0.036\text{s}$

Given Data:
$F=100\text{N}$

Change in momentum can be calculated as:
$\Delta P=2\times 0.15\times 12$
$=3.6$
Now, Impulse can be given as:
$J=F\cdot t$

$\Rightarrow t=\frac{J}{F}=\frac{3.6}{100}=0.036\text{s}$
As, ($J=\Delta P$ )

Thus, we can say that the correct option is $\left(b\right)$.