A ball of mass $0.2 k g$ is thrown vertically upwards by applying a force by hand. If the hand moves $0.2 m$ while applying the force and the ball goes up to $2 m$ height further, find the magnitude of the force.

16 N

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20 N

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22 N

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4 N

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Solution

The correct option is C $22 N$
Given,
$m = 0.2 k g$
$x = 0.2 m$
$g = 10 m / s^{2}$
$h = 2.2 m$
Kinetic energy is equal to the potential energy,
$F . x + m g h = 0$
$| F | = \frac{m g h}{x} = \frac{0.2 \times 10 \times 2.2}{0.2} = 22 N$
The correct option is C.

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Similar questions

A ball of mass 0.2kg is thrown vertically upwards by applying a force by hand. If the hand moves 0.2m while applying the force and the ball goes up to 2m height further, find the magnitude of force. (Consider g = 10m/s²).

Q. A ball of mass

0.2 kg

is thrown vertically upwards by applying a force by hand. If the hand moves

0.2 m

upward while applying the force and the ball goes upto

2 m

height further, find the magnitude of the force (in newtons).
[Take

g = 10 {m/s}^{2}

]

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A ball of mass 0.2 kg is thrown vertically upwards by applying a force by hand. If the hand moves 0.2 m while applying the force and the ball goes up to 2 m height further, find the magnitude of the force.

The correct option is C 22 NGiven,m=0.2kgx=0.2mg=10m/s2h=2.2mKinetic energy is equal to the potential energy,F.x+mgh=0|F|=mghx=0.2×10×2.20.2=22NThe correct option is C.

A ball of mass $0.2 k g$ is thrown vertically upwards by applying a force by hand. If the hand moves $0.2 m$ while applying the force and the ball goes up to $2 m$ height further, find the magnitude of the force.

The correct option is C $22 N$
Given,
$m = 0.2 k g$
$x = 0.2 m$
$g = 10 m / s^{2}$
$h = 2.2 m$
Kinetic energy is equal to the potential energy,
$F . x + m g h = 0$
$| F | = \frac{m g h}{x} = \frac{0.2 \times 10 \times 2.2}{0.2} = 22 N$
The correct option is C.