A ball of mass 0.2 kg moves with a velocity of 20 m/s and it stops in 0.1 s, then the force on the ball is

10 N

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20 N

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40 N

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80 N

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Solution

The correct option is C 40 N
Given, m= 0.2 kg. v = 20 m/s, t = 0.1s

$F = m a = \frac{m Δ v}{Δ t}$

$∴ f = 0. 2 \times \frac{20}{0.1} = 40 N$

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A ball of mass 0.2 kg moves with a velocity of 20 m/s and it stops in 0.1 s, then the force on the ball is

The correct option is C 40 NGiven, m= 0.2 kg. v = 20 m/s, t = 0.1sF=ma=mΔvΔt∴f=0.2×200.1=40N

The correct option is C 40 N
Given, m= 0.2 kg. v = 20 m/s, t = 0.1s

$F = m a = \frac{m Δ v}{Δ t}$

$∴ f = 0. 2 \times \frac{20}{0.1} = 40 N$