A ball of mass 0.5 gram is hit by battery switch giving an impulse of 0.075 N with what velocity does the ball move?

Open in App

Solution

For Ball 1 :

Mass = 0.5 kg

Velocity = 5 m / s

For Ball 2 :

Mass = 1 kg

Velocity = ?

We know that,

Momentum of Ball 1 = Momentum of Ball 2

This can be given by the law of conservation of momentum. Hence we can say that,

Momentum of Ball 1 = Momentum of Ball 2

Momentum of Ball 1 = Mass * Velocity of ball 1

= 0.5 kg * 5 m/s = 2.5 kg.m/s

Momentum of Ball 2 = Mass * Velocity of ball 2

= 1 * v 2.5 kg.m/s = 1 kg * v

=> v = 2.5 kg.m/s / 1 kg = 2.5 m/s

Hence velocity of ball 2 is 2.5 m/s.

Suggest Corrections

Similar questions

Q. A ball of mass 100gm is hit by a hockey stick giving an impulse of 0.075Ns with what velocity does the ball move?

Q. A ball of mass

20

gram hits a wall at an angle of

45^{o}

with a velocity of

15 m / s

. If the ball rebounds at

90^{o}

to the direction of incidence, calculate the impulse received by the ball.

Q. A ball of mass 20 gram hits a wall at an angle of 45 degree with a velocity of 15 metre per second. if the ball rebounds at 90 degree to the direction of incidence, calculate the impulse received by the ball with diagram.

A football of mass $0.5 k g$ moving with a velocity of $10 m s^{- 1}$ hits a pole and, the ball turns back and moves with a velocity of $20 m s^{- 1}$ . Find the impulse and the force exerted on the ball if the force acts for $0.02 s$ .

Q. A ball of mass

20 g

hits a wall at an angle

45^{\circ}

with a velocity of

15 m s^{- 1}

. If the ball rebounds at

90^{\circ}

to the direction of incidence, calculate the impulse received by ball.

Join BYJU'S Learning Program