A ball of mass 1 kg is dropped from a tower. Find power of gravitational force at time t=2 s. $(g = 10 m / s^{2})$

100 W

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200 W

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400 W

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500 W

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Solution

The correct option is B 200 W
Force acting on the body is constant and equal to the gravitational force= $F = m g = 10 N$
Velocity attained by body after $2 s$ is $v = a t = 10 \times 2 = 20 m / s$
Thus power of gravitational force at that time= $F v = 200 W$

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A ball of mass 1 kg is dropped from a tower. Find power of gravitational force at time t=2 s. (g=10m/s2)

The correct option is B 200 WForce acting on the body is constant and equal to the gravitational force=F=mg=10NVelocity attained by body after 2s is v=at=10×2=20m/sThus power of gravitational force at that time=Fv=200W

A ball of mass 1 kg is dropped from a tower. Find power of gravitational force at time t=2 s. $(g = 10 m / s^{2})$

The correct option is B 200 W
Force acting on the body is constant and equal to the gravitational force= $F = m g = 10 N$
Velocity attained by body after $2 s$ is $v = a t = 10 \times 2 = 20 m / s$
Thus power of gravitational force at that time= $F v = 200 W$