A ball of mass 1 kg moving with a velocity of $4 m / s e c$ collides with a stationary ball. The collision is oblique. After the collision the first moves at right angle to its, initial direction with a velocity of $3 m / s$ . The momentum of the second ball (in kg $m / s$ ) after collision would be nearly :

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Solution

The correct option is A 5
As the momentum should be conserved the second ball will have a momentum of 4 kgm/s in the original direction and 3kgm/s in the direction opposite to the first ball after collision.

Therefore the net momentum will be $M = \sqrt{4^{2} + 3^{2}} = 5 k g m / s$

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A ball of mass 1 kg moving with a velocity of 4m/sec collides with a stationary ball. The collision is oblique. After the collision the first moves at right angle to its, initial direction with a velocity of 3m/s. The momentum of the second ball (in kg m/s) after collision would be nearly :

The correct option is A 5As the momentum should be conserved the second ball will have a momentum of 4 kgm/s in the original direction and 3kgm/s in the direction opposite to the first ball after collision.Therefore the net momentum will be M=√42+32=5kgm/s

The correct option is A 5
As the momentum should be conserved the second ball will have a momentum of 4 kgm/s in the original direction and 3kgm/s in the direction opposite to the first ball after collision.

Therefore the net momentum will be $M = \sqrt{4^{2} + 3^{2}} = 5 k g m / s$