wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A ball of mass 1 kg strikes a heavy platform, elastically, moving upwards with a velocity of 5m/s.The speed of the ball just before the collision is 10m/s downwards. Then the impulse imparted by the Platform on the ball is (e=1) :-
876343_835c50b515f7416eacd231c9f1b10e57.png

A
15 Ns
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10 Ns
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
20 Ns
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
30 Ns
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 30 Ns

The speed of the ball in the reference frame of the plank is given as,

v=10+5

v=15m/s

The change in momentum of the ball is the impulse and it is given as,

mv=15+15

=30Ns

Thus, the impulse is 30Ns.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Summary and Misconceptions
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon