A ball of mass 1 kg strikes a heavy platform, elastically, moving upwards with a velocity of 5m/s.The speed of the ball just before the collision is 10m/s downwards. Then the impulse imparted by the Platform on the ball is (e=1) :-
The speed of the ball in the reference frame of the plank is given as,
v=10+5
v=15m/s
The change in momentum of the ball is the impulse and it is given as,
mv=15+15
=30N⋅s
Thus, the impulse is 30N⋅s.