A ball of mass 1 kg thrown upwards, reaches a maximum height of 4 m. Calculate the work done by the force of gravity during this vertical displacement $(g = 10 m / s^{2})$ .

- 40 J

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40 J

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- 80 J

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80 J

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Solution

The correct option is A $- 40 J$
Given, $m a s s o f b a l l, m = 1 k g; g = 10 m / s^{2}$
Force of gravity on the ball,
$F = m g = 1 \times 10 = 10 N$
Vertical displacement of the ball, $s = 4 m$
Since the force and the displacement of the ball are in opposite directions, work done by the force of gravity,
$W = - F \times s$
$= - 10 \times 4 = - 40 J$

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A ball of mass 1 kg thrown upwards, reaches a maximum height of 4 m. Calculate the work done by the force of gravity during this vertical displacement (g=10m/s2).

The correct option is A −40JGiven, massofball,m=1kg;g=10m/s2Force of gravity on the ball,F=mg=1×10=10NVertical displacement of the ball, s=4mSince the force and the displacement of the ball are in opposite directions, work done by the force of gravity, W=−F×s =−10×4=−40J

A ball of mass 1 kg thrown upwards, reaches a maximum height of 4 m. Calculate the work done by the force of gravity during this vertical displacement $(g = 10 m / s^{2})$ .