A ball of mass $100$ g is moving with a velocity of $10$ . The ball is stopped by the boy in $0.2 m s$ . Find the force of the ball?

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Solution

$M a s s o f b a l l = 100 g$

$V e l o c i t y o f b a l l = 10 m / s$

$B a l l s t o p b y b o y i n 0.2 s e c .$

$F o r c e = m a s s \times a c c e l e r a t i o n$

but acceleration=initial velocity - final velocity/time

but initial velocity $= 10 m / s$ and final velocity $= 0 m / s$

$T i m e = 0.2 s e c o n d$

$A c c e l e r a t i o n = \frac{10 - 0}{0.2} = 50$

$F o r c e = m \times a = 100 \times 50 = 500 N e w t o n$

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A ball of mass 100 g is moving with a velocity of 10. The ball is stopped by the boy in 0.2ms. Find the force of the ball?

Massofball=100g Velocityofball=10m/s Ballstopbyboyin0.2sec. Force=mass×acceleration but acceleration=initial velocity - final velocity/time but initial velocity=10m/s and final velocity=0m/s Time=0.2second Acceleration=10−00.2=50 Force=m×a=100×50=500Newton

A ball of mass $100$ g is moving with a velocity of $10$ . The ball is stopped by the boy in $0.2 m s$ . Find the force of the ball?