A ball of mass 100 g is projected with a velocity of 50 m/s at 37∘ from horizontal. Using the concept of impulse, find the magnitude of change in velocity of ball in 2 s (Take g = 10 m/s2)
A
70 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
20 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
30 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B20 m/s Using, |J|=|F|×t=|Δp|=m|ΔV| ⇒|ΔV|=(tm)|F| Only force acting on the ball is mg ∴|ΔV|=tm×mg=gt =10×2 =20 m/s