A ball of mass 12 kg and another ball of mass 6 kg are dropped from a 60 feet tall building. when these balls are at 30 feet. Find the ratio of kinetic energies:

\sqrt{2} : 1

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1:4

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2:1

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1 : \sqrt{2}

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Solution

The correct option is C 2:1
Kinetic energy will be equal to change in Potential energy.
$P . E = m g h$
$K_{1} = m_{1} g h$ , $K_{2} = m_{2} g h$
$∴ \frac{K_{1}}{K_{2}} = \frac{m_{1}}{m_{2}} = 12 / 6 = 2 : 1$

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A ball of mass 12 kg and another ball of mass 6 kg are dropped from a 60 feet tall building. when these balls are at 30 feet. Find the ratio of kinetic energies:

The correct option is C 2:1Kinetic energy will be equal to change in Potential energy.P.E=mghK1=m1gh, K2=m2gh∴K1K2=m1m2=12/6=2:1

The correct option is C 2:1
Kinetic energy will be equal to change in Potential energy.
$P . E = m g h$
$K_{1} = m_{1} g h$ , $K_{2} = m_{2} g h$
$∴ \frac{K_{1}}{K_{2}} = \frac{m_{1}}{m_{2}} = 12 / 6 = 2 : 1$