A ball of mass 12 kg and another of mass 6 kg are dropped from a 60 feet tall building. After a fall of 30 feet each, towards earth, their kinetic energies will be in the ratio of :

\sqrt{2} : 1

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1 : 4

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2 : 1

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1 : \sqrt{2}

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Solution

The correct option is D $2 : 1$
KE $=$ decrease in potential energy $= m g h$
or $K E \propto m$
or $\frac{(K E)_{1}}{(K E)_{2}} = \frac{12}{6} = \frac{2}{1}$

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A ball of mass 12 kg and another of mass 6 kg are dropped from a 60 feet tall building. After a fall of 30 feet each, towards earth, their kinetic energies will be in the ratio of :

The correct option is D 2:1KE = decrease in potential energy =mghor KE∝mor (KE)1(KE)2=126=21

The correct option is D $2 : 1$
KE $=$ decrease in potential energy $= m g h$
or $K E \propto m$
or $\frac{(K E)_{1}}{(K E)_{2}} = \frac{12}{6} = \frac{2}{1}$