A ball of mass 150 g moving at 10 ms^-1 is stopped by a force which acts on it for 0.1 s, then the impulsive force is

70 N

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1500 N

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15 N

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150 N

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Solution

The correct option is
B

15 N
Impulse = Change in momentum
$Impulse = m v - m u = 150 \times 10^{- 3} \times (10 - 0)$
$Impulse = 1.5 N s$
Now, impulse is given as a product of impulsive force and time interval
$Impulse = F Δ t$
$∴ F = \frac{I m p u l s e}{Δ t} = \frac{1.5}{0.1} = 15 N$ .

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A ball of mass 150 g moving at 10 ms-1 is stopped by a force which acts on it for 0.1 s, then the impulsive force is

The correct option is B 15 NImpulse = Change in momentum Impulse =mv−mu=150×10−3×(10−0) Impulse =1.5NsNow, impulse is given as a product of impulsive force and time interval Impulse =FΔt∴F=ImpulseΔt=1.50.1=15N.

A ball of mass 150 g moving at 10 ms^-1 is stopped by a force which acts on it for 0.1 s, then the impulsive force is

The correct option is
B

15 N
Impulse = Change in momentum
$Impulse = m v - m u = 150 \times 10^{- 3} \times (10 - 0)$
$Impulse = 1.5 N s$
Now, impulse is given as a product of impulsive force and time interval
$Impulse = F Δ t$
$∴ F = \frac{I m p u l s e}{Δ t} = \frac{1.5}{0.1} = 15 N$ .