A ball of mass 2 kg and another of mass 4 kg are dropped together from a 60 feet tall building. After a fall of 30 feet, their respective kinetic energies will be in the ratio of

$\sqrt{2} : 1$

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$1 : 2$

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$1 : 2$

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$1 : \sqrt{2}$

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Solution

The correct option is C
$1 : 2$

$\frac{(K . E)_{1}}{(K . E)_{2}} = \frac{m_{1}}{m_{2}} = \frac{2}{4}$ $(K . E)_{1} : (K . E)_{2} = 1 : 2$

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A ball of mass 2 kg and another of mass 4 kg are dropped together from a 60 feet tall building. After a fall of 30 feet, their respective kinetic energies will be in the ratio of

The correct option is C 1:2 (K.E)1(K.E)2=m1m2=24 (K.E)1:(K.E)2=1:2

The correct option is C
$1 : 2$

$\frac{(K . E)_{1}}{(K . E)_{2}} = \frac{m_{1}}{m_{2}} = \frac{2}{4}$ $(K . E)_{1} : (K . E)_{2} = 1 : 2$